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Two finite sets have m and 3 elements re...

Two finite sets have `m` and `3` elements respectively. The total number of subsets of first set is `56` more than the total number of subsets of the second set. The value of `m` is ___________

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To solve the problem step by step, we can follow these instructions: ### Step 1: Understand the problem We have two finite sets, one with `m` elements (let's call it Set A) and another with `3` elements (let's call it Set B). We need to find the value of `m` given that the total number of subsets of Set A is `56` more than the total number of subsets of Set B. ### Step 2: Determine the formula for subsets The total number of subsets of a set with `n` elements is given by the formula \(2^n\). ### Step 3: Calculate the number of subsets for both sets - For Set A (with `m` elements), the number of subsets is \(2^m\). - For Set B (with `3` elements), the number of subsets is \(2^3 = 8\). ### Step 4: Set up the equation based on the problem statement According to the problem, the number of subsets of Set A is `56` more than the number of subsets of Set B. This can be expressed as: \[ 2^m = 2^3 + 56 \] ### Step 5: Substitute the values Substituting the value of \(2^3\): \[ 2^m = 8 + 56 \] \[ 2^m = 64 \] ### Step 6: Express 64 as a power of 2 We know that: \[ 64 = 2^6 \] So we can rewrite the equation as: \[ 2^m = 2^6 \] ### Step 7: Equate the exponents Since the bases are the same, we can equate the exponents: \[ m = 6 \] ### Conclusion The value of \(m\) is \(6\). ---
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