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Find the equation of the circle which to...

Find the equation of the circle which touches the both axes in first quadrant and whose radius is `a`.

Text Solution

Verified by Experts

Given that radius of the circle is a i.e., `(h,k)=(a,a)`

So, the equation of required circle is
`(x-a)^(2)+(y-a)^(2)=a^(2)`
`rArrx^(2)=2ax+a^(2)+y^(2)-2ay+a^(2)=a^(2)`
`rArr x^(2)+y^(2)-2ax-2ay+a^(2)=0`
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