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The line x+3y=0 is a diameter of the cir...

The line x+3y=0 is a diameter of the circle `x^(2)+y^(2)+6x+2y=0`

Text Solution

Verified by Experts

False
Given equation of the circle is
`x^(2)+y^(2)+6x+2y=0`
`therefore` Centre=(-3,-1)
Since given line is x+3y=0.
`rArr-3-3ne`0
So, this line is not diameter of the circle.
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