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Find the equation of the circle which to...

Find the equation of the circle which touches the `x` - axis and whose center is `(1, 2).`

A

`x^(2)+y^(2)-2x-4y+1=0`

B

`x^(2)-y^(2)+2x-6y+2=0`

C

`x^(2)-y^(2)+4x-6y+5=0`

D

`"none of these"`

Text Solution

Verified by Experts

The correct Answer is:
A
Given that , centre of the circle is `(1,2)`

`because` Radius `= 2`
So, the equation of the circle is
`(x-1)^(2)+(y-)^(2)=2^(2)`
`rArr x^(2)-2x+1+y^(2)-4y+4=4`
`rArr x^(2)-2x+y^(2)-4y+1=0`
`rArr x^(2)+y^(2)-2x-4y+1=0`
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