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If the lines 3x-4y+4=0 and 6x-8y-7=0 ar...

If the lines `3x-4y+4=0` and `6x-8y-7=0` are tangents to a circle, then find the radius of the circle.

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The correct Answer is:
D
Given lines
`3x-4y+4=0` …(i)
`6x-8y-7=0`
or `3x-4y-7/2=0`….(ii)
It is clear that lines (i) and (ii) are parallel.
Now distance between them i.e.,
`d=abs((4+7//2)/sqrt(9+16))=abs(((8+7)/2)/5)=3//2`
`therefore` Distance between these line=Diameter of these circle
`therefore` Diameter of the circle = `3/2`
and radius of the circle = `3/4`
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