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Find the eccentricity coordinates of foc...

Find the eccentricity coordinates of foci length of the latus rectum of the following ellipse: `9x^2+2y^2=225`

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Given equation of ellipse, `9x^(2)+25y^(2)=225`
`rArr(x^(2))/25+(y^(2))/9=1`
`rArra=5,b=3`
We know that, `b^(2)=a^(2)(1-e^(2))`
`rArr9=25(1-e^(2))`
`rArr9/25=1-e^(2)`
`rArre^(2)=1-9//25`
`thereforee=sqrt(1-9//25)=sqrt((25-9)/25)`
=`sqrt(16/25)=4//5`
Foci=(`pm`ae,0)=(`pm5xx4//5,0)=(pm4,0)`
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