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Find the equation of the circle having c...

Find the equation of the circle having centre at `(3,-4)` and touching the line `5x+12 y-12=0.`

Text Solution

Verified by Experts

The perpendicular distance from centre `(3,-4)` to the line is ,`d=` `abs((15-48-12)/(sqrt(25+144)))=45/13`

So, the required equation of the circle is `(x-3)^(2)+(y+4)^(2)=(45/13)^(2)`
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Knowledge Check

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    A
    `x^(2)+y^(2)-4x-2y+5=0`
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    B
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    C
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    D
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