Home
Class 11
MATHS
Find the equation of the parabola whose ...

Find the equation of the parabola whose focus is at `(-1,-2)` and the directrix the line `x-2y+3=0`

Text Solution

Verified by Experts

Given that, focus at `F(-1,-2)` and dirctrix is `x-2y+3=0`
Let any point on the parabola be `(x,y)`
`PF=abs((x-2y+3)/(sqrt(1+4)))`
`rArr (x+1)^(2)+(y+2)^(2)=((x-2y+3)^(2))/5`
`rArr5[x^(2)+2x+1+y^(2)+4y+4]=x^(2)+4y^(2)+9-4xy-12y+6x`
`rArr4x^(2)+y^(2)+4x+32y+16=0`
Promotional Banner

Topper's Solved these Questions

  • CONIC SECTIONS

    NCERT EXEMPLAR|Exercise Objective type|13 Videos
  • CONIC SECTIONS

    NCERT EXEMPLAR|Exercise True/False|8 Videos
  • COMPLEX NUMBERS AND QUADRATIC EQUATIONS

    NCERT EXEMPLAR|Exercise OBJECTIVE TYPE QUESTIONS|16 Videos
  • INTRODUCTION TO THREE DIMENSIONAL GEOMETRY

    NCERT EXEMPLAR|Exercise Fillers|16 Videos

Similar Questions

Explore conceptually related problems

Find the equation of the parabola whose focus is (-3,2) and the directrix is x+y=4

Find the equation of the parabola whose: focus is (0,0) and the directrix 2x-y-1=0

Find the equation of the parabola whose focus is at (-1, 1) and the directrix is x+y+1=0 .

Find the equation of the parabola whose: focus is (3,0) and the directrix is 3x+4y=1

The equation of the parabola whose focus is (1,1) and the directrix is x+y+1=0

Find the equation of the parabola whose focus is (5,3) and directrix is the line 3x-4y+1=0.

The equation of the parabola whose focus is (-3,0) and the directrix is x+5=0 is:

Find the equation to the parabola whose focus is (5, 3) and directrix the line 3x-4y+1=0 .

Find the equation of the parabola whose focus is (-1, 2) and directrix is x-2y-15=0 .

Find the equaiton of the parabola whose focus is (0, -2) and directrix is y=2 .