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Find the equation of a circle with origi...

Find the equation of a circle with origin as centre and which circumscribes equilateral triangle whose median of length `3a`

A

`x^(2)+y^(2)=9a^(2)`

B

`x^(2)+y^(2)=16a^(2)`

C

`x^(2)+y^(2)=4a^(2)`

D

`x^(2)+y^(2)=a^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
Given that, length of the median AD=3a
`because` Radius of the circle=`3/2xx`Length of median
`=2/3xx3a=2a`

So, the equation of the circle is `x^(2)+y^(2)=4a^(2)`.
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