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The distance between the foci of a hyper...

The distance between the foci of a hyperbola is 16 and its eccentricity is `sqrt(2)` then equation of the hyperbola is

A

`x^(2)-y^(2)=32`

B

`(x^(2))/4-(y^(2))/9=1`

C

`2x-3y^(2)=7`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
Given that, distance between the foci of hyperbola
i.e., 2ae=16 `rArrae=8`….(i)
and `e=sqrt2`…(ii)
Now, `sqrt2a=8`
`rArr a=4sqrt2`
`becauseb^(2)=a^(2)(e^(2)-1)`
`rArr b^(2)=32(2-1)`
`rArrb^(2)=32`
`therefore (x^(2))/32-(y^(2))/32=1`
`rArrx^(2)-y^(2)=32`
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