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A school has five houses A, B,C,D and E....

A school has five houses A, B,C,D and E. A class has 23 students, 4 from houses A, 8 from house C, 2 from house D and rest from house E. A single student is selected at random to be the class monitor. The probability that the selected student is not from A, B and C is

A

`(4)/(23)`

B

`(6)/(23)`

C

`(8)/(23)`

D

`(17)/(23)`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the probability that a randomly selected student is not from houses A, B, and C. Let's break it down step by step. ### Step 1: Determine the total number of students in the class. The total number of students in the class is given as 23. ### Step 2: Identify the number of students from each house. - Students from house A = 4 - Students from house B = 8 - Students from house C = 5 - Students from house D = 2 - Students from house E = (Total students - Students from A, B, C, D) ### Step 3: Calculate the number of students from house E. First, we need to find the total number of students from houses A, B, C, and D: - Total from A, B, C, and D = 4 (A) + 8 (B) + 5 (C) + 2 (D) = 19 Now, we can find the number of students from house E: - Students from house E = Total students - Total from A, B, C, D - Students from house E = 23 - 19 = 4 ### Step 4: Determine the number of students not from houses A, B, and C. We need to find the students who are not from houses A, B, and C: - Students not from A, B, and C = Students from D + Students from E - Students not from A, B, and C = 2 (D) + 4 (E) = 6 ### Step 5: Calculate the probability. The probability that a randomly selected student is not from houses A, B, and C is given by the formula: \[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \] In this case: - Number of favorable outcomes (students not from A, B, and C) = 6 - Total number of outcomes (total students) = 23 Thus, the probability is: \[ \text{Probability} = \frac{6}{23} \] ### Final Answer: The probability that the selected student is not from houses A, B, and C is \( \frac{6}{23} \). ---

To solve the problem, we need to find the probability that a randomly selected student is not from houses A, B, and C. Let's break it down step by step. ### Step 1: Determine the total number of students in the class. The total number of students in the class is given as 23. ### Step 2: Identify the number of students from each house. - Students from house A = 4 - Students from house B = 8 ...
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