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Apoorv throws two dice once and computes...

Apoorv throws two dice once and computes the product of the numbers appearing on the dice. Peehu throws one side one die and squares the number that appears on it. Who has the better chance of getting the number of 36? Why?

Text Solution

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Approv throws two dice once,
So total number of outcomes=36
Number of outcomes for getting product 36=`1(6^(2)=36)`
Probability for Approv `=(1)/(36)`
Also, Peehu throws one die
So total number of outcomes=6
Number of outcomes for getting square36=`(6^(2)=36)`
Probability for peehu `=(1)/(6)=(6)/(36)`
Hence, Peehu has better chance of getting the number 36.
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