A coin is tossed 3 times. List the possible outcomes. Find the probability of getting
(i) all heads (ii) atleast 2 heads

Explanation

The possible outcomes if a coin is tossed 3 times I
S={(HHH),(TTT),(HTT),(THT),(THH),(HTH),(HHT)}
`therefore n(S)=8`
(i) Let `E_(1)`=Event of getting all heads={(HHH)}
`P(E_(1))=(n(E ))/(n(S))=(1)/(8)`
(ii) Let `E_(2)`=Event of getting alleast 2 heads= {(HHT),(HTH),(THH),(HHH)}
`n(E_(2))=4`
`P(E_(2))=(n(E_(2)))/(n(S))=(4)/(8)=(1)/(2)`