A letter of English alphabet is chosen at random. Determine the probability that the chosen letter is a consonant.

Explanation

We know that in english alphabets, there (5 vowels + 21 consonants) =26 letter. So, total number of outcomes in english alphabets are. N(S)=26
Let E=Event of choosing a english alphbet, which is a consonant ={(b,c,d,f,g,h,j,k,l,m,n,p,q,r,s,t,v,w,x,y,z)}
`therefore n(E)=21`
Hence, required probability= `(n(E))/(n(S))=(21)/(26)`