A die its six faces marked 0,1,1,1,6,6. Two such dice are thrown together and the total is recorded.
(i) How many different scores are responsible
(ii) What is the probability

Explanation

Given, a die has its six faces marked {0,1,1,1,6,6}
`therefore` Total sample space, n(S)=`(6)^(2)=36`
(i) The different score which are possible are 6 scores i.e. 0,1,2,6,7 and 12.
(ii) Let E=Event of getting a sum 7
={(1,6),(1,6),(1,6),(1,6),(1,6),(1,6),(6,1),(6,1),(6,1),(6,1),(6,1),(6,1)}
`therefore n(E)=12`
`therefore P(E)=(n(E))/(n(S))=(12)/(36)=(1)/(3)`