Locate `sqrt(2)`on the number line.

Explanation

`sqrt2 = sqrt(1+1)`

`2 = 1+1`

`(sqrt2)^2 = (1)^2 + (1)^2`

`(sqrt2)^2` is taken as hypotenuse

with centre as O, we can make a triangle and locate `sqrt2`

OA & OC will be the radii of the circle