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Find the HCF of he numbers in each of th...

Find the HCF of he numbers in each of the following , using the prime factorization method :
84 , 98

A

13

B

12

C

15

D

14

Text Solution

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The correct Answer is:
To find the HCF (Highest Common Factor) of the numbers 84 and 98 using the prime factorization method, we will follow these steps: ### Step 1: Prime Factorization of 84 1. Start dividing 84 by the smallest prime number, which is 2. - \( 84 \div 2 = 42 \) 2. Divide 42 by 2 again. - \( 42 \div 2 = 21 \) 3. Now, divide 21 by the next smallest prime number, which is 3. - \( 21 \div 3 = 7 \) 4. Finally, divide 7 by itself (the last prime number). - \( 7 \div 7 = 1 \) So, the prime factorization of 84 is: \[ 84 = 2^2 \times 3^1 \times 7^1 \] ### Step 2: Prime Factorization of 98 1. Start dividing 98 by the smallest prime number, which is 2. - \( 98 \div 2 = 49 \) 2. Now, divide 49 by the next smallest prime number, which is 7. - \( 49 \div 7 = 7 \) 3. Finally, divide 7 by itself. - \( 7 \div 7 = 1 \) So, the prime factorization of 98 is: \[ 98 = 2^1 \times 7^2 \] ### Step 3: Identify Common Prime Factors Now, we will find the common prime factors from both factorizations: - For 84: \( 2^2 \times 3^1 \times 7^1 \) - For 98: \( 2^1 \times 7^2 \) The common prime factors are: - \( 2^1 \) (the minimum power of 2) - \( 7^1 \) (the minimum power of 7) ### Step 4: Calculate the HCF Now, we multiply the common prime factors: \[ HCF = 2^1 \times 7^1 = 2 \times 7 = 14 \] Thus, the HCF of 84 and 98 is **14**. ---
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