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Find the greatest number that will divi...

Find the greatest number that will divide 445, 572 and 699 , leaving remainders 4, 5, 6, respectively.

A

42

B

49

C

70

D

63

Text Solution

AI Generated Solution

The correct Answer is:
To find the greatest number that will divide 445, 572, and 699, leaving remainders 4, 5, and 6 respectively, we can follow these steps: ### Step 1: Adjust the numbers by subtracting the remainders To find a common divisor, we first need to adjust the numbers by subtracting the respective remainders. - For 445, subtract 4: \( 445 - 4 = 441 \) - For 572, subtract 5: \( 572 - 5 = 567 \) - For 699, subtract 6: \( 699 - 6 = 693 \) ### Step 2: Find the highest common factor (HCF) Now we need to find the HCF of the adjusted numbers: 441, 567, and 693. #### Step 2.1: Prime factorization of 441 To find the prime factors of 441: - 441 can be divided by 3: \( 441 \div 3 = 147 \) - 147 can also be divided by 3: \( 147 \div 3 = 49 \) - 49 can be divided by 7: \( 49 \div 7 = 7 \) - 7 is a prime number. So, the prime factorization of 441 is: \( 3^2 \times 7^2 \) #### Step 2.2: Prime factorization of 567 To find the prime factors of 567: - 567 can be divided by 3: \( 567 \div 3 = 189 \) - 189 can also be divided by 3: \( 189 \div 3 = 63 \) - 63 can also be divided by 3: \( 63 \div 3 = 21 \) - 21 can also be divided by 3: \( 21 \div 3 = 7 \) - 7 is a prime number. So, the prime factorization of 567 is: \( 3^4 \times 7^1 \) #### Step 2.3: Prime factorization of 693 To find the prime factors of 693: - 693 can be divided by 3: \( 693 \div 3 = 231 \) - 231 can also be divided by 3: \( 231 \div 3 = 77 \) - 77 can be divided by 7: \( 77 \div 7 = 11 \) - 11 is a prime number. So, the prime factorization of 693 is: \( 3^2 \times 7^1 \times 11^1 \) ### Step 3: Identify common factors Now, we find the common prime factors from the factorizations: - For 3: The minimum power is \( 3^2 \) (from 441 and 693). - For 7: The minimum power is \( 7^1 \) (from 567 and 693). ### Step 4: Calculate the HCF Now we multiply the common prime factors: \[ HCF = 3^2 \times 7^1 = 9 \times 7 = 63 \] ### Conclusion The greatest number that will divide 445, 572, and 699, leaving remainders 4, 5, and 6 respectively, is **63**. ---
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