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The HCF of 144, 180 and 192 is...

The HCF of 144, 180 and 192 is

A

12

B

16

C

18

D

8

Text Solution

AI Generated Solution

The correct Answer is:
To find the Highest Common Factor (HCF) of the numbers 144, 180, and 192, we will follow these steps: ### Step 1: Find the Prime Factorization of Each Number **For 144:** 1. Divide by 2: \(144 \div 2 = 72\) 2. Divide by 2: \(72 \div 2 = 36\) 3. Divide by 2: \(36 \div 2 = 18\) 4. Divide by 2: \(18 \div 2 = 9\) 5. Divide by 3: \(9 \div 3 = 3\) 6. Divide by 3: \(3 \div 3 = 1\) So, the prime factorization of 144 is: \[ 144 = 2^4 \times 3^2 \] **For 180:** 1. Divide by 2: \(180 \div 2 = 90\) 2. Divide by 2: \(90 \div 2 = 45\) 3. Divide by 3: \(45 \div 3 = 15\) 4. Divide by 3: \(15 \div 3 = 5\) 5. Divide by 5: \(5 \div 5 = 1\) So, the prime factorization of 180 is: \[ 180 = 2^2 \times 3^2 \times 5^1 \] **For 192:** 1. Divide by 2: \(192 \div 2 = 96\) 2. Divide by 2: \(96 \div 2 = 48\) 3. Divide by 2: \(48 \div 2 = 24\) 4. Divide by 2: \(24 \div 2 = 12\) 5. Divide by 2: \(12 \div 2 = 6\) 6. Divide by 2: \(6 \div 2 = 3\) 7. Divide by 3: \(3 \div 3 = 1\) So, the prime factorization of 192 is: \[ 192 = 2^6 \times 3^1 \] ### Step 2: Identify Common Factors Now we will identify the common prime factors from the factorizations: - For \(2\): The minimum power is \(2^2\) (from 180). - For \(3\): The minimum power is \(3^1\) (from 192). ### Step 3: Calculate the HCF Now, we multiply the common prime factors: \[ \text{HCF} = 2^2 \times 3^1 = 4 \times 3 = 12 \] ### Conclusion The HCF of 144, 180, and 192 is **12**. ---
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