Home
Class 6
MATHS
Fill in the blank: (i) 9(2)/(3)+…..=19...

Fill in the blank:
(i) `9(2)/(3)+…..=19`
(ii) `6(1)/(6)-?=(29)/(30)`
(iii) `7-5(2)/(3)=` ……..
(iv) `(72)/(90)` reduced to simplest from is …..
(v) `(42)/(54)=(7)/(square)`

Text Solution

AI Generated Solution

The correct Answer is:
Let's solve each part of the question step by step: ### Part (i): **Equation:** \( 9 \frac{2}{3} + \text{?} = 19 \) 1. Convert \( 9 \frac{2}{3} \) to an improper fraction: \[ 9 \frac{2}{3} = \frac{27 + 2}{3} = \frac{29}{3} \] 2. Set up the equation: \[ \frac{29}{3} + \text{?} = 19 \] 3. To isolate the unknown, subtract \( \frac{29}{3} \) from both sides: \[ \text{?} = 19 - \frac{29}{3} \] 4. Convert 19 to a fraction with a denominator of 3: \[ 19 = \frac{57}{3} \] 5. Now perform the subtraction: \[ \text{?} = \frac{57}{3} - \frac{29}{3} = \frac{57 - 29}{3} = \frac{28}{3} \] ### Answer for Part (i): \[ \text{?} = \frac{28}{3} \]
Promotional Banner

Topper's Solved these Questions

  • FRACTIONS

    RS AGGARWAL|Exercise EXERCISE 5G|20 Videos
  • FACTORS AND MULTIPLES

    RS AGGARWAL|Exercise Test paper - 2 (D.)|1 Videos
  • INTEGERS

    RS AGGARWAL|Exercise TEST PAPER - 4 (D)|1 Videos

Similar Questions

Explore conceptually related problems

Fill in the blanks : 6/7 + (-3/5) = ____ + 6/7

Replace square by the correct number in each of the follwing: (i) (2)/(7)=(8)/(square) (ii) (3)/(5)=(square)/(35) (iii) (5)/(8)=(20)/(square) (iv) (45)/(60)=(9)/(square) (v) (40)/(56)=(square)/(7) (vi) (42)/(54)=(7)/(square)

Find the additive inverse of : (i) (5)/(9) " " (ii) (-15)/(8)" " (iii) (9)/(-11)" " (iv) (-6)/(-7)

Fill in the blanks. ( i ) If 9 xx 3^(n)=3^(6), then n=……. ( ii ) (8)^(0)= ? ( iii ) (frac(a)(b))^(-16)=….. ( iv ) (-2)^(-5)=…..

Find (i) (7)/(24)-(17)/(36) (ii) (5)/(63)-((-6)/(21))( iii) (-6)/(13)-(7)/(11)(v)(-2)(1)/(9)-6

Fill in the blanks : (i) (….)divide ((-7)/(5))=(10)/(19) (ii) (……)divide(-3)= (-4)/(15) (iii) (9)/(8)divide (……..) = (-3)/(2) (iv) (-12)+(………) = (-6)/(5)

Fill in the blanks : (i) (-3) + (-9) = ……. (ii) (-7) + (-8) = ….. (iii) (-9) + 16 = ….. (iv) (-13) + 25 = ….. (v) 8 + (-17) = ……….. (vi) 2 + (-12) = ……….

Find the values of :- (i) 2^(4) (ii) 4^(3) (iii) 3^(2) (iv) 5^(3) (v) 9^(4) (vi) 7^(3)

Evaluate: (i) 3 ^(-4) " "(ii) (-4) ^(3) " "(iii) ((3)/(4))^(-2)" "(iv) ((-2)/(3)) ^(-5) " "(v) ((5)/(7))^(0)