`5a - [a^(2) - {2a (1 - a + 4a^(2)) - 3a(a^(2) - 5a -3)}] - 8a`

(5a^(3)-4a^(2)+3a+18)/(a^(2)-2a+3)

Simplify (a^(2) - 8ab - 5) + (3ab - 4a^(2) + 8)

Add: (i) 3x, 7x (ii) 7y, -9y (iii) 2xy, 5xy, -xy (iv) 3x, 2y (v) 2x^(2), -3x^(2), 7x^(2) (vi) 7xyz, -5xyz, 9xyz, - 8xyz (vii) 6a^(3) , - 4a^(3), 10 a^(3), - 8a^(3) (viii) x^(2) - a^(2), -5x^(2) + 2a^(2), -4x^(2) + 4a^(2)

2 (4)/(5) - 1 (3)/(8) + 3 (1)/(2) = ?

If the equation a^(2) x^(2) + (a^(2) - 5a + 4) xy + (3a - 2) y^(2) - 8x + 12y - 4 = 0 represents a circle , then : a =

Take away ((8)/(5)x^(2) - (2)/(3)x^(3) + (3)/(2)x -1) from ((x^(3))/(5) - (3)/(2)x^(2) + (2)/(3)x + (1)/(4))

What must be added to the sum of 2a^(2)-3a+7,-5a^(2)-2a-11 and 3a^(2)+5a-8 to get 0?

4(1)/(2) xx 4(1)/(3) -8(1)/(3) -: 5(2)/(3) =?