A room is 8 m long and 6 m wide. Its floor is to be covered with rectangular tiles of size 25 cm by 20 cm. how many tiles will be required ?

Options

A. 960
B. 600
C. 500
D. 650

Answer

To solve the problem of how many tiles are required to cover the floor of a room that is 8 m long and 6 m wide with tiles that are 25 cm by 20 cm, we can follow these steps:

### Step 1: Calculate the area of the room
The area of a rectangle can be calculated using the formula:
\[ \text{Area} = \text{Length} \times \text{Width} \]

For the room:
- Length = 8 m
- Width = 6 m

So,
\[ \text{Area of the room} = 8 \, \text{m} \times 6 \, \text{m} = 48 \, \text{m}^2 \]

### Step 2: Convert the dimensions of the tiles from cm to m
The dimensions of the tiles are given in centimeters. We need to convert them to meters:
- Length of the tile = 25 cm = \( \frac{25}{100} \) m = 0.25 m
- Width of the tile = 20 cm = \( \frac{20}{100} \) m = 0.20 m

### Step 3: Calculate the area of one tile
Now, we can calculate the area of one tile using the same area formula:
\[ \text{Area of one tile} = \text{Length of tile} \times \text{Width of tile} \]

So,
\[ \text{Area of one tile} = 0.25 \, \text{m} \times 0.20 \, \text{m} = 0.05 \, \text{m}^2 \]

### Step 4: Calculate the number of tiles required
To find the total number of tiles needed, we divide the area of the room by the area of one tile:
\[ \text{Number of tiles} = \frac{\text{Area of the room}}{\text{Area of one tile}} \]

So,
\[ \text{Number of tiles} = \frac{48 \, \text{m}^2}{0.05 \, \text{m}^2} = 960 \]

### Step 5: Conclusion
Therefore, the total number of tiles required to cover the floor of the room is **960 tiles**.

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