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A shopkeeper gains rs. 1 on each pen and...

A shopkeeper gains rs. 1 on each pen and loses 40 paise on each pencil. He sells 45 pens and some pencils losing Rs. 5 in all. How many pencils does he sell?

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To solve the problem step by step, we will follow the given information and set up the equations accordingly. ### Step 1: Understand the Gains and Losses - The shopkeeper gains Rs. 1 on each pen sold. - The shopkeeper loses 40 paise (which is Rs. 0.40) on each pencil sold. ### Step 2: Calculate Total Gain from Pens - The shopkeeper sells 45 pens. - Gain from selling 45 pens = 45 pens × Rs. 1/pen = Rs. 45. ### Step 3: Set Up the Equation for Total Loss - The total loss incurred by the shopkeeper is Rs. 5. - Let the number of pencils sold be \( x \). - Loss from selling \( x \) pencils = \( x \times 0.40 \) (since he loses Rs. 0.40 on each pencil). ### Step 4: Write the Total Gain and Loss Equation - The total gain from pens minus the total loss from pencils should equal the overall loss: \[ \text{Total Gain from Pens} - \text{Total Loss from Pencils} = \text{Total Loss} \] Substituting the values we have: \[ 45 - 0.40x = -5 \] ### Step 5: Solve the Equation - Rearranging the equation gives: \[ 45 + 5 = 0.40x \] \[ 50 = 0.40x \] - Now, divide both sides by 0.40 to find \( x \): \[ x = \frac{50}{0.40} \] - Calculating the right side: \[ x = 125 \] ### Conclusion - The shopkeeper sells **125 pencils**.
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