Home
Class 7
MATHS
Fill in the blanks: i {(-13) + 27} + (-4...

Fill in the blanks:
i {(-13) + 27} + (-41) = (-13) + {27 + (...)}
ii (-26) + {(-49) + (-83)} = {(-26) + (-49)} + (...)
iii 53+(-37) = (-37)+ (...)
iv (-68) + (-76) = (...) + (-68)
v (-72)+ (...) =-72
vi -(-83)=….
vii (-60)-(...) = -59
viii (-31)-+-(...) = -40

Text Solution

AI Generated Solution

The correct Answer is:
Let's solve the question step by step: ### Question: Fill in the blanks: 1. {(-13) + 27} + (-41) = (-13) + {27 + (...)} ### Step 1: Solve the left side of the equation Calculate the expression inside the curly brackets: \[ (-13) + 27 = 14 \] So, we rewrite the left side: \[ 14 + (-41) \] ### Step 2: Calculate \(14 + (-41)\) This can be simplified as: \[ 14 - 41 = -27 \] Thus, the left side becomes: \[ -27 \] ### Step 3: Rewrite the right side Now, we rewrite the right side of the equation: \[ (-13) + {27 + (...)} = -27 \] ### Step 4: Isolate the blank To find the value that fills the blank, we need: \[ (-13) + (27 + x) = -27 \] Where \(x\) is the value we need to find. ### Step 5: Solve for \(x\) First, isolate \(27 + x\): \[ 27 + x = -27 + 13 \] \[ 27 + x = -14 \] Now, subtract 27 from both sides: \[ x = -14 - 27 \] \[ x = -41 \] ### Conclusion for Part i: The blank in the first part is: \[ -41 \] --- ### Part ii: 2. (-26) + {(-49) + (-83)} = {(-26) + (-49)} + (...) ### Step 1: Solve the left side Calculate: \[ (-49) + (-83) = -49 - 83 = -132 \] So, the left side becomes: \[ -26 + (-132) = -26 - 132 = -158 \] ### Step 2: Rewrite the right side Now, we rewrite the right side: \[ {(-26) + (-49)} + x = -158 \] ### Step 3: Calculate \((-26) + (-49)\) \[ -26 - 49 = -75 \] Thus, we have: \[ -75 + x = -158 \] ### Step 4: Solve for \(x\) Isolate \(x\): \[ x = -158 + 75 \] \[ x = -83 \] ### Conclusion for Part ii: The blank in the second part is: \[ -83 \] --- ### Part iii: 3. 53 + (-37) = (-37) + (...) ### Step 1: Calculate the left side \[ 53 + (-37) = 53 - 37 = 16 \] ### Step 2: Rewrite the right side We have: \[ (-37) + x = 16 \] ### Step 3: Solve for \(x\) Isolate \(x\): \[ x = 16 + 37 \] \[ x = 53 \] ### Conclusion for Part iii: The blank in the third part is: \[ 53 \] --- ### Part iv: 4. (-68) + (-76) = (...) + (-68) ### Step 1: Calculate the left side \[ -68 - 76 = -144 \] ### Step 2: Rewrite the right side We have: \[ x + (-68) = -144 \] ### Step 3: Solve for \(x\) Isolate \(x\): \[ x = -144 + 68 \] \[ x = -76 \] ### Conclusion for Part iv: The blank in the fourth part is: \[ -76 \] --- ### Part v: 5. (-72) + (...) = -72 ### Step 1: Isolate the blank Let \(x\) be the blank: \[ -72 + x = -72 \] ### Step 2: Solve for \(x\) \[ x = -72 + 72 \] \[ x = 0 \] ### Conclusion for Part v: The blank in the fifth part is: \[ 0 \] --- ### Part vi: 6. -(-83) = ... ### Step 1: Simplify The negative of a negative is positive: \[ -(-83) = 83 \] ### Conclusion for Part vi: The answer is: \[ 83 \] --- ### Part vii: 7. (-60) - (...) = -59 ### Step 1: Isolate the blank Let \(x\) be the blank: \[ -60 - x = -59 \] ### Step 2: Solve for \(x\) Rearranging gives: \[ -x = -59 + 60 \] \[ -x = 1 \] Thus, \[ x = -1 \] ### Conclusion for Part vii: The blank in the seventh part is: \[ -1 \] --- ### Part viii: 8. (-31) - - (...) = -40 ### Step 1: Rewrite This can be rewritten as: \[ -31 + x = -40 \] ### Step 2: Solve for \(x\) Isolate \(x\): \[ x = -40 + 31 \] \[ x = -9 \] ### Conclusion for Part viii: The blank in the eighth part is: \[ -9 \] ---
Promotional Banner

Topper's Solved these Questions

  • INTEGERS

    RS AGGARWAL|Exercise EXERCISE 1B|9 Videos
  • INTEGERS

    RS AGGARWAL|Exercise EXERCISE 1C|3 Videos
  • INTEGERS

    RS AGGARWAL|Exercise Examples (DIVISION OF INTEGERS)|5 Videos
  • FRACTIONS

    RS AGGARWAL|Exercise TEST PAPER-2|26 Videos
  • LINEAR EQUATION IN ONE VARIABLE

    RS AGGARWAL|Exercise TEST PAPER 7D|1 Videos

Similar Questions

Explore conceptually related problems

Fill in the blanks. i (-35) xx ... =35 ii (-53) xx (...) =-53 iii (-14) xx(...)= (-16) xx (-14) iv (-21) xx(...)= 0 v (-119) + 17 = (...) vi (-247)+ (...)= 13 vii (...)+31=0 viii (...) +(-19)=-8

Fill in the blanks : (i) (-3) + (-9) = ……. (ii) (-7) + (-8) = ….. (iii) (-9) + 16 = ….. (iv) (-13) + 25 = ….. (v) 8 + (-17) = ……….. (vi) 2 + (-12) = ……….

Evaluate I 15+(-8) ii (-16)+9 iii (-7)+(-23) iv (-32)+47 v 53+(-26) vi (-48)+(-36)

Fill in the blanks: i 72 /4-(...) = -4 ii -36 /4-(...) = -4 iii (.......)/(-4) = 24 iv (.......)/25 = 0 v (........)/ (-1) = 36 vi (.......)/1 = -37 vii 39 /(.......) = -1 viii 1/(......... ) = -1 ix -1 / (.........) = -1

Fill in the blanks by appropriate symbol gt " or " lt : (i) 0 …….. 7 (ii) 0 ……… -3 (iii) -5 ……… -2 (iv) -15 …….. 13 (v) -231 …. -132 (vi) -6 …… 6

Find the additive inverse of : (i)5 (ii) -9 (iii) (3)/(14) (iv) (-11)/(15) (v) (15)/(-4) (vi) (-18)/(-13) (vii) 0 (viii) (1)/(-6)

Evaluate : (i) i^(23)" "(ii) i^(998)" "(iii)i^(-998)" "(iv) i^(-71) (v) (sqrt(-1))^(91)" "(vi) (i^(37)xx i^(-61))" "(vii) i^(-1)