Milk is sold at Rs `37 3/4` per litre. Find the cost of `6 2/5` litres of milk.

Answer

To find the cost of \(6 \frac{2}{5}\) litres of milk when the price per litre is \(Rs. 37 \frac{3}{4}\), we can follow these steps:

### Step 1: Convert the mixed numbers to improper fractions
First, we need to convert both \(37 \frac{3}{4}\) and \(6 \frac{2}{5}\) into improper fractions.

For \(37 \frac{3}{4}\):
\[ 37 \frac{3}{4} = \frac{(37 \times 4) + 3}{4} = \frac{148 + 3}{4} = \frac{151}{4} \]

For \(6 \frac{2}{5}\):
\[ 6 \frac{2}{5} = \frac{(6 \times 5) + 2}{5} = \frac{30 + 2}{5} = \frac{32}{5} \]

### Step 2: Calculate the total cost
Now, we can find the total cost by multiplying the cost per litre by the number of litres.
\[ \text{Total Cost} = \text{Cost per litre} \times \text{Number of litres} = \frac{151}{4} \times \frac{32}{5} \]

### Step 3: Multiply the fractions
To multiply the fractions, we multiply the numerators and the denominators:
\[ \text{Total Cost} = \frac{151 \times 32}{4 \times 5} = \frac{4832}{20} \]

### Step 4: Simplify the fraction
Now, we simplify \(\frac{4832}{20}\):
\[ \frac{4832 \div 4}{20 \div 4} = \frac{1208}{5} \]

### Step 5: Convert the improper fraction to a mixed number
Now, we convert \(\frac{1208}{5}\) into a mixed number:
\[ 1208 \div 5 = 241 \quad \text{(remainder 3)} \]
So, we can write it as:
\[ 241 \frac{3}{5} \]

### Final Answer
The cost of \(6 \frac{2}{5}\) litres of milk is \(Rs. 241 \frac{3}{5}\).

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