Subtract the sum of `(-36)/(11)` and `(49)/(22)` from the sum of `(33)/(8)` and `(-19)/(4)`

Answer

To solve the problem, we need to follow these steps:

### Step 1: Calculate the sum of \(-\frac{36}{11}\) and \(\frac{49}{22}\).

To add these two fractions, we need a common denominator. The least common multiple (LCM) of 11 and 22 is 22.

\[ -\frac{36}{11} = -\frac{36 \times 2}{11 \times 2} = -\frac{72}{22} \]

Now we can add:

\[ -\frac{72}{22} + \frac{49}{22} = \frac{-72 + 49}{22} = \frac{-23}{22} \]

### Step 2: Calculate the sum of \(\frac{33}{8}\) and \(-\frac{19}{4}\).

Again, we need a common denominator. The LCM of 8 and 4 is 8.

\[ -\frac{19}{4} = -\frac{19 \times 2}{4 \times 2} = -\frac{38}{8} \]

Now we can add:

\[ \frac{33}{8} - \frac{38}{8} = \frac{33 - 38}{8} = \frac{-5}{8} \]

### Step 3: Subtract the sum from Step 1 from the sum from Step 2.

We need to subtract \(-\frac{23}{22}\) from \(-\frac{5}{8}\):

\[ -\frac{5}{8} - \left(-\frac{23}{22}\right) = -\frac{5}{8} + \frac{23}{22} \]

Now we need a common denominator for 8 and 22. The LCM of 8 and 22 is 88.

Convert both fractions:

\[ -\frac{5}{8} = -\frac{5 \times 11}{8 \times 11} = -\frac{55}{88} \]

\[ \frac{23}{22} = \frac{23 \times 4}{22 \times 4} = \frac{92}{88} \]

Now we can add:

\[ -\frac{55}{88} + \frac{92}{88} = \frac{-55 + 92}{88} = \frac{37}{88} \]

### Final Answer:
\[ \frac{37}{88} \]

---