To solve the equation \( \frac{1}{4}x + \frac{1}{6}x = \frac{1}{2}x + \frac{3}{4} \), we will follow these steps:
### Step 1: Combine like terms on the left side
We start with the equation:
\[
\frac{1}{4}x + \frac{1}{6}x = \frac{1}{2}x + \frac{3}{4}
\]
To combine the \( x \) terms on the left side, we need a common denominator for \( \frac{1}{4} \) and \( \frac{1}{6} \). The least common multiple (LCM) of 4 and 6 is 12.
### Step 2: Rewrite each term with the common denominator
Convert each fraction:
\[
\frac{1}{4}x = \frac{3}{12}x, \quad \frac{1}{6}x = \frac{2}{12}x, \quad \frac{1}{2}x = \frac{6}{12}x
\]
Now, substituting these values back into the equation gives:
\[
\frac{3}{12}x + \frac{2}{12}x = \frac{6}{12}x + \frac{3}{4}
\]
### Step 3: Combine the left side
Now combine the \( x \) terms on the left:
\[
\frac{3}{12}x + \frac{2}{12}x = \frac{5}{12}x
\]
So the equation now looks like:
\[
\frac{5}{12}x = \frac{6}{12}x + \frac{3}{4}
\]
### Step 4: Move all \( x \) terms to one side
Subtract \( \frac{6}{12}x \) from both sides:
\[
\frac{5}{12}x - \frac{6}{12}x = \frac{3}{4}
\]
This simplifies to:
\[
-\frac{1}{12}x = \frac{3}{4}
\]
### Step 5: Solve for \( x \)
To isolate \( x \), multiply both sides by -12:
\[
x = -12 \times \frac{3}{4}
\]
Calculating the right side:
\[
x = -9
\]
### Final Answer
Thus, the solution to the equation is:
\[
\boxed{-9}
\]
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