AM is median of `triangleABC`, prove that (AB+BC+CA)`gt2AM`.

In the given figure ,P is a point on the side BC of triangleABC .Prove tat (AB+BC+AC)GT2AP

AM is a median of s triangle ABC. Is AB+BC+CA>2AM? (Consider the sides of triangles Delta ABM and Delta AMC.

In DeltaABC, D is any point on side BC. Prove that AB+BC+CA gt 2AD

In the figure, AD is perpendicular to BC, prove that AB+AC gt 2AD .

If O is point in the exterior of triangleABC ,show that 2(OA+OB+OC)gt(AB+BC+CA)

AD is a median of the Delta ABC .Is it trure AB+BC+CA gt 2 AD ? Give reason for your answer

AD BE and CF are the medians of a Delta ABC .Prove that 2(AD+BE+CF)<3(AB+BC+CA)<4(AD+BE+CF)

Seg AD is the median of /_ABC and AM perp BC. Prove that :(i)AC^(2)=AD^(2)+BC xx DM+((BC)/(2))^(2)(ii)AB^(2)=AD^(2)-BC xx DM+((BC)/(2))^(2)

In triangle ABC, AD is a median. Prove that AB + AC gt 2AD

In triangleABC , in the usual notation, the area is (1)/(2) bc sq. units AD is the median to BC. Prove that /_ABC= (1)/(2) /_ADC .