Find the area of a rhombus in which
Q(i) each side = 12 cm and height = 7.5 cm,
(ii) each side = 2 dm and height = 12.6 cm. 

Answer

To find the area of a rhombus, we can use the formula:

\[ \text{Area} = \text{base} \times \text{height} \]

where the base is the length of one side of the rhombus and the height is the perpendicular distance from the base to the opposite side.

### Solution:

**(i) For the first rhombus:**
1. **Given:**
- Each side (base) = 12 cm
- Height = 7.5 cm

2. **Using the formula for area:**
\[ \text{Area} = \text{base} \times \text{height} = 12 \, \text{cm} \times 7.5 \, \text{cm} \]

3. **Calculating the area:**
\[ \text{Area} = 12 \times 7.5 = 90 \, \text{cm}^2 \]

**(ii) For the second rhombus:**
1. **Given:**
- Each side (base) = 2 dm
- Height = 12.6 cm

2. **Convert the base from decimeters to centimeters:**
\[ 2 \, \text{dm} = 2 \times 10 \, \text{cm} = 20 \, \text{cm} \]

3. **Using the formula for area:**
\[ \text{Area} = \text{base} \times \text{height} = 20 \, \text{cm} \times 12.6 \, \text{cm} \]

4. **Calculating the area:**
\[ \text{Area} = 20 \times 12.6 = 252 \, \text{cm}^2 \]

### Final Answers:
- Area of the first rhombus = 90 cm²
- Area of the second rhombus = 252 cm²