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A diagonal of a quadrilateral is 26 cm a...

A diagonal of a quadrilateral is 26 cm and the perpendiculars drawn to it from the opposite vertices are 12.8 cm and 11.2 cm. Find the area of the quadrilateral.

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To find the area of the quadrilateral, we can use the formula for the area of a quadrilateral when the lengths of the diagonals and the perpendiculars from the opposite vertices to the diagonal are known. The area \( A \) can be calculated using the formula: \[ A = \frac{1}{2} \times d \times (h_1 + h_2) \] where: - \( d \) is the length of the diagonal, - \( h_1 \) and \( h_2 \) are the lengths of the perpendiculars from the opposite vertices to the diagonal. ### Step-by-Step Solution: 1. **Identify the given values**: - Length of the diagonal \( d = 26 \) cm - Length of the first perpendicular \( h_1 = 12.8 \) cm - Length of the second perpendicular \( h_2 = 11.2 \) cm 2. **Substitute the values into the area formula**: \[ A = \frac{1}{2} \times 26 \times (12.8 + 11.2) \] 3. **Calculate the sum of the perpendiculars**: \[ h_1 + h_2 = 12.8 + 11.2 = 24 \text{ cm} \] 4. **Now substitute this sum back into the area formula**: \[ A = \frac{1}{2} \times 26 \times 24 \] 5. **Calculate \( \frac{1}{2} \times 26 \)**: \[ \frac{1}{2} \times 26 = 13 \] 6. **Now multiply by 24**: \[ A = 13 \times 24 = 312 \text{ cm}^2 \] ### Final Answer: The area of the quadrilateral is \( 312 \text{ cm}^2 \).
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RS AGGARWAL-MENSURATION-EXERCISE 20D
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