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Find the area of a right triangle having...

Find the area of a right triangle having base = 24 cm and hypotenuse = 25 cm.

A

48 `cm^2`

B

54 `cm^2`

C

64 `cm^2`

D

84 `cm^2`

Text Solution

AI Generated Solution

The correct Answer is:
To find the area of a right triangle with a base of 24 cm and a hypotenuse of 25 cm, we can follow these steps: ### Step 1: Identify the given values - Base (b) = 24 cm - Hypotenuse (h) = 25 cm ### Step 2: Use the Pythagorean theorem In a right triangle, the Pythagorean theorem states that: \[ h^2 = b^2 + p^2 \] where \( p \) is the perpendicular (height) of the triangle. ### Step 3: Substitute the known values into the Pythagorean theorem \[ 25^2 = 24^2 + p^2 \] ### Step 4: Calculate the squares - \( 25^2 = 625 \) - \( 24^2 = 576 \) Now substitute these values into the equation: \[ 625 = 576 + p^2 \] ### Step 5: Solve for \( p^2 \) Rearranging the equation gives: \[ p^2 = 625 - 576 \] \[ p^2 = 49 \] ### Step 6: Find the value of \( p \) Taking the square root of both sides: \[ p = \sqrt{49} \] \[ p = 7 \text{ cm} \] ### Step 7: Calculate the area of the triangle The area \( A \) of a right triangle is given by the formula: \[ A = \frac{1}{2} \times \text{base} \times \text{height} \] Substituting the values we have: \[ A = \frac{1}{2} \times 24 \times 7 \] ### Step 8: Perform the multiplication \[ A = \frac{1}{2} \times 168 \] \[ A = 84 \text{ cm}^2 \] ### Final Answer The area of the right triangle is \( 84 \text{ cm}^2 \). ---
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