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Simplify: ((4)/(7)+(-8)/(9) +(-5)/(21) +...

Simplify: `((4)/(7)+(-8)/(9) +(-5)/(21) +(1)/(3))`.

A

`(2)/(9)`

B

`(-1)/(9)`

C

`(-2)/(9)`

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To simplify the expression \(\frac{4}{7} + \left(-\frac{8}{9}\right) + \left(-\frac{5}{21}\right) + \frac{1}{3}\), we will follow these steps: ### Step 1: Identify the denominators The denominators in the expression are 7, 9, 21, and 3. ### Step 2: Find the Least Common Multiple (LCM) We need to find the LCM of the denominators (7, 9, 21, 3). - The prime factorization of each number is: - \(7 = 7^1\) - \(9 = 3^2\) - \(21 = 3^1 \times 7^1\) - \(3 = 3^1\) The LCM will take the highest power of each prime: - \(3^2\) from 9 - \(7^1\) from 7 Thus, the LCM is \(63\). ### Step 3: Convert each fraction to have the common denominator Now we will convert each fraction to have a denominator of 63: 1. \(\frac{4}{7} = \frac{4 \times 9}{7 \times 9} = \frac{36}{63}\) 2. \(-\frac{8}{9} = -\frac{8 \times 7}{9 \times 7} = -\frac{56}{63}\) 3. \(-\frac{5}{21} = -\frac{5 \times 3}{21 \times 3} = -\frac{15}{63}\) 4. \(\frac{1}{3} = \frac{1 \times 21}{3 \times 21} = \frac{21}{63}\) ### Step 4: Combine the fractions Now we can combine all the fractions: \[ \frac{36}{63} - \frac{56}{63} - \frac{15}{63} + \frac{21}{63} \] Combining the numerators: \[ 36 - 56 - 15 + 21 = 36 - 56 = -20 \] \[ -20 - 15 = -35 \] \[ -35 + 21 = -14 \] So we have: \[ \frac{-14}{63} \] ### Step 5: Simplify the fraction Now we simplify \(\frac{-14}{63}\): The greatest common divisor (GCD) of 14 and 63 is 7. So we divide both the numerator and the denominator by 7: \[ \frac{-14 \div 7}{63 \div 7} = \frac{-2}{9} \] ### Final Answer The simplified form of the expression is: \[ \frac{-2}{9} \]
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Knowledge Check

  • Simplify : 1(4)/(7)+1(3)/(5)+1(1)/(3)

    A
    `5(47)/(105)`
    B
    `4(58)/(105)`
    C
    `4(53)/(105)`
    D
    `5(43)/(105)`
  • Simplify : ((5)/(6) + (7)/(8)"of" (4)/(5) div (3)/(4) "of" (9)/(10))/(8 (1)/(3) - ((4)/(1 - (7)/(8))"of 2" (1)/(4)) div (7)/(9) "of 12") "of 6" (1)/(2) + 5(1)/(9)

    A
    `24 (1)/(4)`
    B
    `24 (3)/(4)`
    C
    `22 (1)/(2)`
    D
    `23 (1)/(3)`
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