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Divakaran deposited a sum of Rs 6250 in ...

Divakaran deposited a sum of Rs 6250 in the Allahabad Bank for 1 year, compunded half-yearly at 8% per annum. Find the compound interest he gets.

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To solve the problem step by step, we will calculate the compound interest earned by Divakaran on his deposit of Rs. 6250 compounded half-yearly at an interest rate of 8% per annum for 1 year. ### Step 1: Identify the given values - Principal (P) = Rs. 6250 - Rate of interest (R) = 8% per annum - Time (T) = 1 year Since the interest is compounded half-yearly, we need to adjust the rate and time accordingly. ### Step 2: Adjust the rate and time for half-yearly compounding - The half-yearly rate of interest = R/2 = 8%/2 = 4% - The number of compounding periods in 1 year = 2 (since it is compounded half-yearly) ### Step 3: Use the compound interest formula The formula for compound interest when compounded multiple times a year is: \[ A = P \left(1 + \frac{r}{100}\right)^{nt} \] Where: - \( A \) = Amount after time \( t \) - \( P \) = Principal amount - \( r \) = Rate of interest per compounding period - \( n \) = Number of times interest is compounded per year - \( t \) = Time in years In our case: - \( P = 6250 \) - \( r = 4 \) (half-yearly rate) - \( n = 2 \) (compounding twice a year) - \( t = 1 \) ### Step 4: Substitute the values into the formula \[ A = 6250 \left(1 + \frac{4}{100}\right)^{2 \times 1} \] \[ A = 6250 \left(1 + 0.04\right)^{2} \] \[ A = 6250 \left(1.04\right)^{2} \] ### Step 5: Calculate \( (1.04)^{2} \) \[ (1.04)^{2} = 1.0816 \] ### Step 6: Calculate the amount \( A \) \[ A = 6250 \times 1.0816 \] \[ A = 6760 \] ### Step 7: Calculate the compound interest (CI) The compound interest is given by: \[ CI = A - P \] \[ CI = 6760 - 6250 \] \[ CI = 510 \] ### Final Answer The compound interest Divakaran gets after 1 year is **Rs. 510**. ---
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