Rs 6000 for 2 years at 9% per annum compunded annually.

Answer

To solve the problem of finding the compound interest on Rs. 6000 for 2 years at an interest rate of 9% per annum compounded annually, we can follow these steps:

### Step 1: Identify the given values
- Principal (P) = Rs. 6000
- Rate of interest (R) = 9% per annum
- Time (T) = 2 years

### Step 2: Convert the rate of interest to a decimal
To use the formula, we need to convert the percentage into a decimal:
\[ R = \frac{9}{100} = 0.09 \]

### Step 3: Use the compound interest formula
The formula for compound interest is:
\[ A = P \left(1 + R\right)^T \]
Where:
- \( A \) = Amount after time \( T \)
- \( P \) = Principal
- \( R \) = Rate of interest (in decimal)
- \( T \) = Time (in years)

### Step 4: Substitute the values into the formula
Substituting the known values into the formula:
\[ A = 6000 \left(1 + 0.09\right)^2 \]
\[ A = 6000 \left(1.09\right)^2 \]

### Step 5: Calculate \( (1.09)^2 \)
Now, we calculate \( (1.09)^2 \):
\[ (1.09)^2 = 1.1881 \]

### Step 6: Calculate the total amount
Now we can find \( A \):
\[ A = 6000 \times 1.1881 \]
\[ A = 7128.60 \]

### Step 7: Calculate the compound interest
To find the compound interest (CI), we subtract the principal from the amount:
\[ CI = A - P \]
\[ CI = 7128.60 - 6000 \]
\[ CI = 1128.60 \]

### Final Result
The compound interest on Rs. 6000 for 2 years at 9% per annum compounded annually is Rs. 1128.60.

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