Home
Class 8
MATHS
In a model of a ship, the mast is 9 cm h...

In a model of a ship, the mast is 9 cm high, while the mast of the actual ship is 15 m high. If the length of the ship is 35 metres, how long is the model ship?

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the concept of direct proportions. Here’s how we can find the length of the model ship based on the given information. ### Step-by-Step Solution: 1. **Convert Measurements to the Same Unit**: - The height of the actual ship's mast is given as 15 m. We need to convert this to centimeters. - \( 15 \text{ m} = 15 \times 100 = 1500 \text{ cm} \) 2. **Identify the Proportions**: - We have the height of the model ship's mast as 9 cm and the height of the actual ship's mast as 1500 cm. - We can set up a proportion based on the heights: \[ \frac{\text{Model Height}}{\text{Actual Height}} = \frac{\text{Model Length}}{\text{Actual Length}} \] - Let the length of the model ship be \( x \) cm and the actual length of the ship is given as 35 m, which we also need to convert to centimeters: - \( 35 \text{ m} = 35 \times 100 = 3500 \text{ cm} \) 3. **Set Up the Proportion**: - Now we can set up the proportion: \[ \frac{9 \text{ cm}}{1500 \text{ cm}} = \frac{x \text{ cm}}{3500 \text{ cm}} \] 4. **Cross-Multiply to Solve for \( x \)**: - Cross-multiplying gives us: \[ 9 \times 3500 = 1500 \times x \] - Calculate \( 9 \times 3500 \): \[ 9 \times 3500 = 31500 \] - Thus, we have: \[ 31500 = 1500x \] 5. **Solve for \( x \)**: - Divide both sides by 1500 to isolate \( x \): \[ x = \frac{31500}{1500} \] - Calculate \( \frac{31500}{1500} \): \[ x = 21 \] 6. **Conclusion**: - The length of the model ship is \( 21 \text{ cm} \). ### Final Answer: The length of the model ship is **21 cm**.
Promotional Banner

Topper's Solved these Questions

  • DIRECT AND INVERSE PROPORTIONS

    RS AGGARWAL|Exercise EXERCISE 12B|15 Videos
  • DIRECT AND INVERSE PROPORTIONS

    RS AGGARWAL|Exercise EXERCISE 12C|10 Videos
  • DIRECT AND INVERSE PROPORTIONS

    RS AGGARWAL|Exercise TEST PAPER -12 (Fill in the blanks )|5 Videos
  • DATA HANDLING

    RS AGGARWAL|Exercise Exercise 21C|11 Videos
  • EXPONENTS

    RS AGGARWAL|Exercise TEST PAPER-2|18 Videos

Similar Questions

Explore conceptually related problems

In a model of a ship,the mast is 9cm high, while the mast of the actual ship is 12m high. If the length of the ship is 28m, how long is the model ship?

A model of a ship is made to a scale of 1:200 . If the length of the model is 4 m, the length of the ship is

The model of a ship shown is of height 3.5 cm. The actual height of the ship is 210 cm if the scale chosen is 1: 60.

From the Masthead of a ship, the angle of Depression of boat is 60^@ , If the mast head is 150 m long , then the distance of the boat from the ship is :

From the top of the lighthouse , an observer looks at a ship and finds the angle of depression to be 60^(@) . IF the height of the lighthouse is 84 metre , then find how far is the ship from the lighthouse ? ( sqrt(3) = 1.73 )

What is the length of the longest rod that can be placed in a room which is 3 metres long, 4 metres broad and 5 metres high ? (m metres)

From a top of a lighthouse, an observer looks at the ship and find the angle of depression to be 45^(@) . If the height of the lighthouse is 1000m , then how far is that ship from the lighthouse.