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A person of mass 50 kg stands on a weigh...

A person of mass 50 kg stands on a weighing scale on a lift . If the lift is descending with a downward acceleration of `9ms^(-2)` what would be the reading of the weighing scale? `(g =10ms^(-2)) ` .

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When a lift descends with a downward acceleration a the apparent weight of a body of mass m is given by
w' = R = m (g-a)
Mass of the person m = 50 kg
Descending acceleration a = 9 m/ `s^(2)`
Apparent weight of the person,
R = m(g-a)
= 50 (10-9)
= 50 N
`therefore` Reading of the weighing scale = `(R)/(g) = (50)/(10) = 5 ` kg .
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