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A woman throws an object of mass 500 g w...

A woman throws an object of mass 500 g with a speed of `25 m s^(-1)` .
(a) What is the impulse imparted to the object ?
(b) If the object hitts a wall and rebounds with the half the original speed , what is the change in momentum of the object ?

Text Solution

Verified by Experts

Mass of the object (m) = 500 g = `0.5` kg
Speed of the object (v) = 25 m/s
(a) Impulse imparted to the object = change in momentum
= mv - mu
= m(v-u)
= `0.5 (25-0) = 12.5` N-s
(b) Velocity of the object after rebounding = `-(25)/(2) m//s`
v' = -12.5 m/s
`therefore` Change in momentum = m(v'-v)
= `0.5 (-12.5 - 25 ) = -18.75`N-s
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