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A block of mass M is held against a roug...

A block of mass M is held against a rough vertical wall by pressing it with a finger . If the coefficient of friction between the block and the wall is `mu` and the acceleration due to gravity is g , calculate the minimum force required to be applied by the finger to hold the block against the wall.

Text Solution

Verified by Experts

Given , mass of the block = M
Coefficient of friction between the block and the wall = `mu`
Let a factor F be applied on the block to hold the block against the wall . The normal reaction of mass be N and force of friction acting upward be f in equilibrium , vertical and horizontal forces should be balanced separately.
`therefore " " f = Mg " " .......(i)`
and `" " F = N " " .....(ii)`

But force of friction (f) = `mu N`
= `mu F " " ["using Eq." (ii) - (iii)`]
From Eqs. (i) and (iii) , we get `mu F = Mg`
or `" " F = (Mg)/(mu)`
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Knowledge Check

  • A block of mass M is held against a rough vertical wall by pressing it with a finger. If the coefficient of friction between the block and the wall is mu and the acceleration due to gravity is g, what is the minimum force required to be applied by the finger to hold the block against the wall?

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    `mu Mg`
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    `M g`
    C
    `(Mg )/(mu)`
    D
    `2 mu M g`
  • A block of mass 0.1 is held against a wall applying a horizontal force of 5N on block. If the coefficient of friction between the block and the wall is 0.5, the magnitude of the frictional force acting on the block is:

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    2.5N
    B
    0.98N
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