A helicopter of mass 2000 kg rises with a vertical acceleration of `15ms^-2`. The total mass of the crew and passengers is 500 kg. Give the magnitude and direction of the (g`=10ms^-2`)
(a) Force on the floor of the helicopter by the crew and passengers.
(b) action of the rotor of the helicopter on the surrounding air.
(c ) force on the helicopter dur to the surrounding air.

Explanation

Given mass of helicopter `(m_(1))` = 2000 kg
Mass of the crew and passengeres `m_(2) = 500` kg
Acceleration in vertical direction a = 15 m/ `s^(2) (uarr)` and g = 10 m/ `s^(2) (darr)`
(a) Force on the floor of the helicopter by the crew and passengers
`m_(2)(g +a ) = 500 (10 + 15) N`
`500 xx 25 N = 12500 N`
(b) Acting of the rotor of the helicopter on the surronding air = `(m_(1) + m_(2)) (g + a)`
= `(2000 + 500) xx (10 + 15) = 2500 xx 25`
= `625000 N` (downward)
(c) Force on the helicopter due to the surrounding air
= reaction of force applied by helicopter .
= 62500 N (upward)