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E^(θ) values of some redox couples are g...

`E^(θ)` values of some redox couples are given below. On the basis of these values choose the correct option.
`E^(θ)` values: `Brt_(2)//Br^(-) = +1.90`
`Ag^(+)//Ag(s)=+0.80`
`Cu^(2+)//Cu(s)=+0.34, I_(2)(s)//I^(-)=+0.54`

A

Cu will reduce `Br^(-)`

B

Cu will reduce Ag

C

Cu will reduce `I^(-)`

D

Cu will reduce `Br_(2)`

Text Solution

Verified by Experts

The correct Answer is:
d
Given that `E^(@)` values of
`Br//Br^(-)=+1.90V`
`Ag//Ag^(+)=-0.80V`
`Cu^(2+)//Cu(s)=+0.34V`
`I^(-)//I_(2)(s)=0.54V`
`Br^(-)//Br_(2)=-1.90V`
The `E^(@)` values show that copper will reduce `Br_(2)`, If the `E^(@)` of the following redox reaction is positive.
`2Cu+Br_(2)toCuBr_(2)`
Now, `CutoCu^(2+)+2e^(-), E^(@)=-0.34V`
`(Br_(2)+2e^(-)to2Br^(-), E=+1.09V)/(Cu+2Br_(2)toCuBr_(2),E^(@)=+0.75V)`
Since, `E^(@)` of this reaction is positive, therfore, Cu can reduce `Br_(2)`.
While other reaction will give negative value.
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