The largest oxidation number exhibited by an element depends on its outer eletronic configuration. With which of the following outer electronic configurations the element will exhibit largest oxidation number ?

Options

A. `3d^(2)4s^(2)`
B. `3d^(3)4s^(2)`
C. `3d^(5)4s^(1)`
D. `3d^(5)4s^(2)`

Answer

d

Explanation

Highest oxidation number of any transition element =(n-1)d electrons + ns electrons. Therefore, large the number of electrons in the 3d-orbitals, higher is the maximum oxidation number
(a) `3d^(1)4s^(2)=3``" "`(b)`3d^(3)4s^(2)=3+2=5`
( c)`3d^(5)4s^(1)=5+1=6`and`" "`(d) `3d^(5)4s^(2)=5+2-7`
Thus, option (d) is correct