An object `5 cm` in length is held `25 cm` away from a converging lens of focal length `10 cm`. Draw the ray diagram and find the position, size and the nature of the image formed.

Explanation

Height of the Object, `h_(0)=5cm`
Distance of the object from converging lens, u = - 25 cm
Focal length of converging lens, f = 10 cm
Using lens formula,
`1/v-1/u=1/f`
`1/v=1/f+1/u=1/10-1/25=15/250`
`v=250/15=16.66 cm`
Also, for a converging lens,`(H_(i))/(h_(0))=v/u`
`h_(i)=v/uxxh_(0)(50x5)/(3x(-25))=10/-3=-3.3cm`
Thus, the image is inverted and formed at a distance of 16.7 cm behind the lens and measures 3.3 cm. The ray diagram is shown below.