In Doppler effect source,observer both are moves away from each other,Appearent frequency heared by observer is

Doppler’s effect can be observed for -

A sound source has frequency f. Source and observer both have same speed.For the apparent frequency observed by observer match the following.

A source of sound emitting a note of frequency 200 Hz moves towards an observer with a velocity v equal to the velocity of sound. If the observer also moves away from the source with the same velocity v, the apparent frequency heard by the observer is

If a source emitting waves of frequency f moves towards an observer with a velocity (v)/(4) and the observer moves away from the source with a velocity (v)/(6) , the apparent frequency as heard by the observer will be (v=velocity of sound)

The source producing sound and an observer both are moving along the direction of propagation of sound waves. If the respective velocities of sound, source and an observer are v, v_(s) and v_(0) , then the apparent frequency heard by the observer will be (n = frequency of sound)

In the absence of air source and observer moves away 20 m/s. The frequency observed by the observer is 1800 Hz and velocity of sound in air is 340 m/s then find original frequency of source

A source emits a frequency of "290Hz" .An observer is moving away from the source with a velocity "20ms^(-1)" and the source is moving away from the observer with a velocity "10ms^(-1)" .The wind is blowing in a direction from the observer to the source with a velocity "5ms^(-1)" .The apparent frequency heard by the observer is (Velocity of sound in air "=343ms^(-1)" )

A source moves away from an obeserver with a certain speed, and the ratio of actual to the apparent frequency as heard by the observer in eta . If the two approach each other with the same speed, then find the ratio.

If the source is moving away from the observer, then the apparent frequency …………..