The radii the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm respectively . The curved surface area of the bucket is

Options

A. `4950 cm^(2)`
B. `4951 cm^(2)`
C. `4952 cm^(2)`
D. `4952 cm^(2)`

Answer

A

Explanation

Given, the radius of the top of the bucket , R = 28 cm
and the radius of the bottom of the bucket , r= 7 cm
Slant height of the bucket , l = 45 cm
`therfore` Curved surface area of the bucket `= pi l (R+ r) = pi xx 454 (28 +7) [therefore "curved surface area of frustum of a cone" = pi (R + r)l]`
`= pi xx 45 xx 35 = (22)/(7) xx 45 xx 35 = 4950 cm^(2)`