Asolid cone of radius r and height h is placed over a solid cylinder having same base radius and height as that of a cone,. The total surface area of the combined solid is `pi [sqrt(r^(2) + h^(2)) +3r +2h]`

Explanation

False
We know that , total surface area of cone of radius, r
and " "height, h = Curved surface Area + area of base `= pirl + pir^(2)`
where, " "`l= sqrt(h^(2) + r^(2))`
and total surface area of a cylinder of bases radiur, r and height , h = Curved surface area + Area of both bases `= 2 pi rh + pil^(2)`
Hence, when we placed a cone over a cylinder, then one base in common for both .
So, total surface area of the combined solid
` = [pirl + 2pirh + pi^(2) = pir[l + 2h +r]`
` =pi [sqrt(r^(2) + h^(2)) + 2h +r]`