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In a triangle ABC, it is known that AB=A...

In a triangle ABC, it is known that AB=AC. Suppose D is the mid-point of AC and BD=BC=2. Then the area of the triangle ABC is-

A

2

B

`2sqrt2`

C

`sqrt7`

D

`2sqrt7`

Text Solution

Verified by Experts

The correct Answer is:
C


We know
`AB^(2)+BC^(2)=2(CD^(2)+BD^(2))`
`AB^(2)+4=2((AB^(2))/(4)+4)`
`AB^(2)+4=(AB^(2))/(4)+8`
`(AB^(2))/(2)=4`
`AB^(2)=8`
`AB=2sqrt2`
Now
Area `=(1)/(2)xx2xxsqrt7=sqrt7`
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