Home
Class 11
PHYSICS
Find the gravitational potential at the ...

Find the gravitational potential at the site of a geostationary satellites . Assume the height of the satellite to be 4200 km from the centre of Earth.
(Mass of Earth `=6.0xx10^(24)kg)` .

Text Solution

Verified by Experts

`M=6.0xx10^(24)kg, R+h=42000xx10^(3)m`
`=4.2xx10^(7)m`
Gravitational potential `=(GM)/(R+h)=(6.67xx10^(-11)xx6xx10^(24))/(4.2xx10^(7))`
`=9.528xx10^(6)J/Kg`
Gravitational potential `=9.53xx10^(6)Jkg^(-1)`
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    SUBHASH PUBLICATION|Exercise FIVE MARKS QUESTIONS WITH ANSWERS|7 Videos

  • ANNUAL EXAMINATION QUESTION PAPER WITH ANSWER SOUTH 2019

    SUBHASH PUBLICATION|Exercise PART-D|9 Videos

  • KINETIC THEORY

    SUBHASH PUBLICATION|Exercise NUMERICALS WITH SOLUTIONS|19 Videos

Similar Questions

Explore conceptually related problems

At what distance from the centre of the Earth do all the geostationary satellites orbit?

A satellite orbits the Earth at a height of 400 km above the surface . How much energy must be expected to Rocket the satellite out of Earth ' s gravitational influence ? Mass of the satellite = 200 kg , mass of Earth =6.0xx10^(24)kg, radius of Earth =6.4xx10^(6)m,G=6.67xx10^(-11)Nm^(2)kg^(-2)

What is a period of revolution of earth satellite ? Ignore the height of satellite above the surface of earth. Given : The value of gravitational acceleration g= 10 m s^(-2) Radius of earta R_(E)= 6400 km . Take pi=3.14 .

Two heavy spheres each of mass 100 kg and radius 0.10m are placed 1. 0m apart on a horizontal table. What is the gravitational field and potent at the mid point of the line joining the centre of the spheres ? (M_(E)=6.0xx10^(24)kg,R_(E)=6.4xx10^(6)m)