Home
Class 11
PHYSICS
A star , 2 .5 times the mass of sum , co...

A star , 2 .5 times the mass of sum , collapse to a size of 12 km with a speed of 1.2 rps . T the object placed on the surface remains stuck to the surface due to gravity ? [ mass of sun `=2xx10^(30)kg`]

Text Solution

Verified by Experts

`g=(GM)/(R^(2))=(6.67xx10^(-11)xx25xx2xx10^(30))/(12xx10^(3))^(2)`
`g=0.2316xx10^(13)ms^(-2)`
`omega^(2) R = (1.2xx2pi)^(2)(1.2xx10^(7))=6.8xx10^(8)ms^(-2)`
Since `g " gt"omega ^(2)R` , the object remains stuck to its surface.
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    SUBHASH PUBLICATION|Exercise FIVE MARKS QUESTIONS WITH ANSWERS|7 Videos
  • ANNUAL EXAMINATION QUESTION PAPER WITH ANSWER SOUTH 2019

    SUBHASH PUBLICATION|Exercise PART-D|9 Videos
  • KINETIC THEORY

    SUBHASH PUBLICATION|Exercise NUMERICALS WITH SOLUTIONS|19 Videos

Similar Questions

Explore conceptually related problems

The acceleration due to gravity on the surface of the Moon is 1.7ms^(-2) . What is the time period of a simple pendulum on the surface of the Moon, if its time period on the surface of Earth is 3.5 s? (g on the surface of the Earth is 9.8ms^(-2) ).

A fully loaded boeing aircraft has a mass of 3.3 times 10^5 Kg . Its total wing area is 500 m^2 . It is in level flight with a speed of 960 km//h (a) Estimate the pressure difference between the lower and upper surfaces of the wings (b) Estimate the fractional increase in the speed of the air on the surface of the wing relative to the lower surface.[ The density of air is p= 1.2 kg m^-3 ]

The mass of ship is 2 xx 10^7 kg. On applying a force of 25xx10^5 N, it is displaced to 25 metres, the speed of ship is

A body of mass 5 kg moving with a velocity of 6 m s^(-1) collide with another body of mass 2 kg which is at rest. Afterwards they move in the same direction as before. If the velocity of the body of mass 2 kg 10 ms^(-1) , find the velocity and kinetic energy to the body of mass 5 kg.

In an atom, an electron is moving with a speed of 6200 m/s which the position of an electron can be locates is (h=6.6xx10^(-34)kgm^(2)s^(-1) , mass of electron e_(m)=9.1xx10^(-31)kg)