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Find :int(sqrtx+1/sqrtx)dx....

Find :`int(sqrtx+1/sqrtx)dx`.

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The correct Answer is:
` int ( x ^ ( 1//2) + x ^ ( -1//2 ) ) dx = ( x ^ (1//2 + 1 ) ) /( 1//2 + 1 ) + ( x ^ ( -1//2 + 1 ) ) /( -1//2 + 1 ) = ( x ^ ( 3//2 ))/ ( 3//2 ) = (2 ) /( 3 ) x ^ ( 3//2 ) + 2 x ^ (1//2 ) `
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