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In a Delta ABC with vertices A(1,2) , B ...

In a `Delta ABC` with vertices A(1,2) , B (2,3) and C (3,1) and `angleA =cos ^(-1)(4/5) , angle B = angle C = cos ^(-1) (1/sqrt10)` , then find the circumcentre of the `DeltaABC.`

Text Solution

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The correct Answer is:
`(11/6,2)`
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In a Delta ABC with vertices A(1,2), B(2,3) and C(3, 1) and angle A = angle B = cos^(-1)((1)/(sqrt(10))), angle C = cos^(-1)((4)/(5)) , then find the circumentre of Delta ABC .

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Knowledge Check

  • Consider the Delta ABC with vertices A( - 2 , 3) , B (2 , 1) and C (1 ,2) What is the Circumcentre of the Delta ABC ?

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    B
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    A
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    B
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    C
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    D
    (2, 0)

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